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#중첩 dict

python

by bumychoi 2024. 7. 8. 16:53

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#중첩 dict
d={"group1":[
    {"name":"Park","age":"32","sex":"Male"},
    {"name":"Cho","age":"44","sex":"Famale"},
    {"name":"Kang","age":"39","sex":"Famale","married":"No"},
],
"group2":[
    {"name":"Kim","age":"23","sex":"Male","married":"Yes"},
    {"name":"Lee","age":"37","sex":"Male","married":"No"},
],
"type":{"a":"employee","b":"officer","c":"director","d":"manager","e":"service provider"}

}

#방법1
ex1 = "name:{0},age:{1},type:{2}".format(d["group2"][0]["name"],d["group2"][0]["age"],d["type"]["b"])
print(ex1)

ex2 = "name:{0},age:{1},type:{2}".format(d.get("group2")[0].get("name"),d.get("group2")[0].get("age"),d.get("type").get("b"))
print(ex2)

 

 

name:Kim,age:23,type:officer
name:Kim,age:23,type:officer

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